如何在两个不同长度的字典上迭代？

dict1 = {'a': 1, 'b': 2, 'c': 3}
dict2 = {'x': 10, 'y': 20}

# 获取较短字典的长度
min_len = min(len(dict1), len(dict2))

# 使用zip()函数进行迭代
for i, j in zip(dict1.items(), dict2.items()):
    key1, value1 = i
    key2, value2 = j
    print(f"dict1: key={key1}, value={value1}")
    print(f"dict2: key={key2}, value={value2}")

# 处理剩余的字典元素
if len(dict1) > min_len:
    for key, value in list(dict1.items())[min_len:]:
        print(f"dict1: key={key}, value={value}")
elif len(dict2) > min_len:
    for key, value in list(dict2.items())[min_len:]:
        print(f"dict2: key={key}, value={value}")