如何在使用List.generate方法时显示List<DropDownItem<String>>？[颤动]

class DropDownItem<T> {
  final T value;
  final String label;

  DropDownItem(this.value, this.label);
}

List<DropDownItem<String>> dropDownItems = [
  DropDownItem('value1', 'Label 1'),
  DropDownItem('value2', 'Label 2'),
  DropDownItem('value3', 'Label 3'),
];

List<Widget> dropDownWidgets = List.generate(
  dropDownItems.length,
  (index) => DropdownMenuItem<String>(
    value: dropDownItems[index].value,
    child: Text(dropDownItems[index].label),
  ),
);

DropdownButton<String>(
  items: dropDownWidgets,
  onChanged: (value) {
    // 处理选中的值
  },
);