如何在列表中以特定的方式交换项目？

def swap_items(lst, index1, index2):
    lst[index1], lst[index2] = lst[index2], lst[index1]

# 示例
my_list = [1, 2, 3, 4, 5]
swap_items(my_list, 1, 3)
print(my_list)  # 输出: [1, 4, 3, 2, 5]

function swapItems(arr, index1, index2) {
    [arr[index1], arr[index2]] = [arr[index2], arr[index1]];
}

// 示例
let myList = [1, 2, 3, 4, 5];
swapItems(myList, 1, 3);
console.log(myList);  // 输出: [1, 4, 3, 2, 5]

import java.util.Arrays;

public class SwapExample {
    public static void swapItems(int[] arr, int index1, int index2) {
        int temp = arr[index1];
        arr[index1] = arr[index2];
        arr[index2] = temp;
    }

    public static void main(String[] args) {
        int[] myList = {1, 2, 3, 4, 5};
        swapItems(myList, 1, 3);
        System.out.println(Arrays.toString(myList));  // 输出: [1, 4, 3, 2, 5]
    }
}

def safe_swap_items(lst, index1, index2):
    if 0 <= index1 < len(lst) and 0 <= index2 < len(lst):
        lst[index1], lst[index2] = lst[index2], lst[index1]
    else:
        print("索引越界")

# 示例
my_list = [1, 2, 3, 4, 5]
safe_swap_items(my_list, 1, 10)  # 输出: 索引越界

import threading

def thread_safe_swap_items(lst, index1, index2):
    with threading.Lock():
        lst[index1], lst[index2] = lst[index2], lst[index1]

# 示例（多线程环境）
my_list = [1, 2, 3, 4, 5]
t1 = threading.Thread(target=thread_safe_swap_items, args=(my_list, 1, 3))
t2 = threading.Thread(target=thread_safe_swap_items, args=(my_list, 2, 4))
t1.start()
t2.start()
t1.join()
t2.join()
print(my_list)  # 输出结果取决于线程执行顺序