如何在完成源文件时覆盖响应状态码[ByteString，_]？

fetch('source_file.html')
  .then(function(response) {
    // 修改响应状态码为200
    response.status = 200;
    return response.text();
  })
  .then(function(data) {
    // 处理响应数据
    console.log(data);
  })
  .catch(function(error) {
    // 处理错误
    console.log(error);
  });

from flask import Flask, make_response

app = Flask(__name__)

@app.route('/source_file')
def source_file():
    # 处理源文件
    response = make_response('Source file content')
    response.status_code = 200  # 修改响应状态码为200
    return response

if __name__ == '__main__':
    app.run()

import unittest
from my_app import app

class MyTestCase(unittest.TestCase):
    def test_source_file(self):
        with app.test_client() as client:
            response = client.get('/source_file')
            response.status_code = 200  # 修改响应状态码为200
            self.assertEqual(response.status_code, 200)

if __name__ == '__main__':
    unittest.main()