如何在忽略空格的同时匹配另一个字符串中的字符串

function removeSpaces(str) {
  return str.replace(/\s/g, '');
}

function kmpSearch(text, pattern) {
  const n = text.length;
  const m = pattern.length;
  const lps = computeLPSArray(pattern);
  
  let i = 0; // 在text中的索引
  let j = 0; // 在pattern中的索引
  
  while (i < n) {
    if (text[i] === pattern[j]) {
      i++;
      j++;
    }
    
    if (j === m) {
      return true; // 匹配成功
    } else if (i < n && text[i] !== pattern[j]) {
      if (j !== 0) {
        j = lps[j - 1];
      } else {
        i++;
      }
    }
  }
  
  return false; // 匹配失败
}

function computeLPSArray(pattern) {
  const m = pattern.length;
  const lps = new Array(m).fill(0);
  
  let len = 0;
  let i = 1;
  
  while (i < m) {
    if (pattern[i] === pattern[len]) {
      len++;
      lps[i] = len;
      i++;
    } else {
      if (len !== 0) {
        len = lps[len - 1];
      } else {
        lps[i] = 0;
        i++;
      }
    }
  }
  
  return lps;
}

const text = "Hello, world!";
const pattern = "low";

const textWithoutSpaces = removeSpaces(text);
const patternWithoutSpaces = removeSpaces(pattern);

const isMatch = kmpSearch(textWithoutSpaces, patternWithoutSpaces);

console.log(isMatch);