如何在没有条件语句的情况下创建不同的类？

# 定义抽象的云服务接口
class CloudService:
    def __init__(self, name):
        self.name = name
    
    def deploy(self):
        pass

# 创建不同类型的云服务类
class EC2(CloudService):
    def deploy(self):
        print("Deploying EC2 instance...")

class S3(CloudService):
    def deploy(self):
        print("Deploying S3 bucket...")

# 创建云服务工厂类
class CloudServiceFactory:
    @staticmethod
    def create_cloud_service(service_type):
        if service_type == "EC2":
            return EC2("EC2")
        elif service_type == "S3":
            return S3("S3")
        else:
            raise ValueError("Invalid service type")

# 使用工厂类创建不同类型的云服务实例
service_type = "EC2"
cloud_service = CloudServiceFactory.create_cloud_service(service_type)
cloud_service.deploy()