如何在没有表单的情况下传递POST变量？

// 创建一个XMLHttpRequest对象
var xhr = new XMLHttpRequest();

// 配置请求类型、URL以及是否异步处理
xhr.open('POST', 'your-server-url', true);

// 设置请求头，告诉服务器我们发送的是表单数据
xhr.setRequestHeader('Content-Type', 'application/x-www-form-urlencoded');

// 发送请求
xhr.send('key1=value1&key2=value2');

// 处理响应
xhr.onreadystatechange = function () {
    if (xhr.readyState === 4 && xhr.status === 200) {
        console.log(xhr.responseText);
    }
};

fetch('your-server-url', {
    method: 'POST',
    headers: {
        'Content-Type': 'application/x-www-form-urlencoded'
    },
    body: 'key1=value1&key2=value2'
})
.then(response => response.text())
.then(data => console.log(data))
.catch(error => console.error('Error:', error));

curl -X POST -d "key1=value1&key2=value2" your-server-url

const http = require('http');

const data = JSON.stringify({
    key1: 'value1',
    key2: 'value2'
});

const options = {
    hostname: 'your-server-host',
    port: 80,
    path: '/your-server-path',
    method: 'POST',
    headers: {
        'Content-Type': 'application/json',
        'Content-Length': data.length
    }
};

const req = http.request(options, res => {
    console.log(`STATUS: ${res.statusCode}`);
    res.setEncoding('utf8');
    res.on('data', chunk => {
        console.log(`BODY: ${chunk}`);
    });
});

req.on('error', e => {
    console.error(`problem with request: ${e.message}`);
});

req.write(data);
req.end();