如何在没有2个导出的情况下显示图像？

<img src="image.jpg" alt="图像">

from flask import Flask, send_file

app = Flask(__name__)

@app.route('/')
def display_image():
    return send_file('image.jpg', mimetype='image/jpeg')

if __name__ == '__main__':
    app.run()

const COS = require('cos-nodejs-sdk-v5');
const fs = require('fs');

const cos = new COS({
    SecretId: 'your-secret-id',
    SecretKey: 'your-secret-key',
});

exports.main_handler = async (event, context, callback) => {
    const params = {
        Bucket: 'your-bucket',
        Region: 'your-region',
        Key: 'image.jpg',
    };

    const downloadPath = '/tmp/image.jpg';

    await new Promise((resolve, reject) => {
        cos.getObject(params, (err, data) => {
            if (err) {
                reject(err);
            } else {
                fs.writeFileSync(downloadPath, data.Body);
                resolve();
            }
        });
    });

    return {
        statusCode: 200,
        headers: {
            'Content-Type': 'image/jpeg',
        },
        body: fs.readFileSync(downloadPath).toString('base64'),
        isBase64Encoded: true,
    };
};