如何在满足某些条件的列表中找到第n个顺序值的索引？

def find_nth_value_index(lst, n, condition):
    count = 0
    for i, value in enumerate(lst):
        if condition(value):
            count += 1
        if count == n:
            return i
    return -1  # 返回-1表示未找到满足条件的第n个顺序值

# 示例用法
my_list = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
n = 3
condition = lambda x: x % 2 == 0  # 查找偶数的索引
index = find_nth_value_index(my_list, n, condition)
print("第{}个满足条件的值的索引为：{}".format(n, index))