如何在满足特定条件时阻止C++模板类方法的实例化？

template <typename T>
class MyClass {
public:
    template <typename U>
    void MyMethod() {
        static_assert(std::is_same<T, U>::value, "T and U must be the same type");
        // Method implementation
    }
};

template <typename T>
class MyClass {
public:
    template <typename U, typename = std::enable_if_t<std::is_same<T, U>::value>>
    void MyMethod() {
        // Method implementation
    }
};

template <typename T>
class MyClass {
public:
    template <typename U>
    void MyMethod() {
        // Default implementation
    }
};

template <typename T>
class MyClass<T*> {
public:
    template <typename U>
    void MyMethod() = delete; // 阻止指针类型的实例化
};