如何在输出中显示大于8128的完全数

def is_perfect_number(num):
    factors = []
    for i in range(1, num):
        if num % i == 0:
            factors.append(i)
    if sum(factors) == num:
        return True
    else:
        return False

def display_perfect_numbers(limit):
    for num in range(8129, limit+1):
        if is_perfect_number(num):
            print(num)

display_perfect_numbers(100000)