如何在C#中对二维数组的行进行随机排列

using System;

class Program
{
    static void Main()
    {
        // 创建一个示例二维数组
        int[,] array = new int[,]
        {
            { 1, 2, 3 },
            { 4, 5, 6 },
            { 7, 8, 9 },
            { 10, 11, 12 }
        };

        // 获取数组的行数和列数
        int rows = array.GetLength(0);
        int cols = array.GetLength(1);

        // 将二维数组转换为一维数组
        int[] flattenedArray = new int[rows * cols];
        int index = 0;
        for (int i = 0; i < rows; i++)
        {
            for (int j = 0; j < cols; j++)
            {
                flattenedArray[index++] = array[i, j];
            }
        }

        // 随机排列一维数组
        Random rand = new Random();
        for (int i = flattenedArray.Length - 1; i > 0; i--)
        {
            int j = rand.Next(i + 1);
            int temp = flattenedArray[i];
            flattenedArray[i] = flattenedArray[j];
            flattenedArray[j] = temp;
        }

        // 将一维数组重新转换为二维数组
        int[,] shuffledArray = new int[rows, cols];
        index = 0;
        for (int i = 0; i < rows; i++)
        {
            for (int j = 0; j < cols; j++)
            {
                shuffledArray[i, j] = flattenedArray[index++];
            }
        }

        // 输出随机排列后的二维数组
        for (int i = 0; i < rows; i++)
        {
            for (int j = 0; j < cols; j++)
            {
                Console.Write(shuffledArray[i, j] + " ");
            }
            Console.WriteLine();
        }
    }
}