如何在C++中获取Linux上当前焦点窗口的几何形状？

#include <X11/Xlib.h>

int main() {
    Display* display = XOpenDisplay(NULL);
    Window focusWindow;
    XGetInputFocus(display, &focusWindow, RevertToNone);

    XWindowAttributes windowAttributes;
    XGetWindowAttributes(display, focusWindow, &windowAttributes);

    int windowX = windowAttributes.x;
    int windowY = windowAttributes.y;
    int windowWidth = windowAttributes.width;
    int windowHeight = windowAttributes.height;

    // 打印窗口几何形状信息
    printf("Window Geometry:\n");
    printf("X: %d\n", windowX);
    printf("Y: %d\n", windowY);
    printf("Width: %d\n", windowWidth);
    printf("Height: %d\n", windowHeight);

    XCloseDisplay(display);
    return 0;
}