如何在ExpandableListView的子项中更改按钮的可见性？

public class MyExpandableListAdapter extends BaseExpandableListAdapter {
    private List<String> groupList;
    private List<List<String>> childList;
    private List<Boolean> buttonVisibilityList;

    public MyExpandableListAdapter(List<String> groupList, List<List<String>> childList, List<Boolean> buttonVisibilityList) {
        this.groupList = groupList;
        this.childList = childList;
        this.buttonVisibilityList = buttonVisibilityList;
    }

    @Override
    public View getChildView(int groupPosition, int childPosition, boolean isLastChild, View convertView, ViewGroup parent) {
        // 获取子项布局
        LayoutInflater inflater = LayoutInflater.from(parent.getContext());
        View view = inflater.inflate(R.layout.child_item_layout, parent, false);

        // 获取按钮控件
        Button button = view.findViewById(R.id.button);

        // 根据按钮可见性标志位设置按钮可见性
        boolean isButtonVisible = buttonVisibilityList.get(groupPosition);
        if (isButtonVisible) {
            button.setVisibility(View.VISIBLE);
        } else {
            button.setVisibility(View.GONE);
        }

        return view;
    }

    // 其他方法省略...

}