如何在Guzzlehttp中获取上传的文件路径？

composer require guzzlehttp/guzzle

use GuzzleHttp\Client;
use GuzzleHttp\Psr7\Request;

$client = new Client();

$request = new Request('POST', 'http://example.com/upload', [
    'multipart' => [
        [
            'name'     => 'file',
            'contents' => fopen('/path/to/file', 'r'), // 替换为实际文件路径
        ],
    ],
]);

$response = $client->send($request);

$body = $response->getBody();
$data = json_decode($body, true);
$fileUrl = $data['file_url']; // 假设响应中返回了文件的URL