如何在Java中对json字符串中的字段进行重新排序

import com.fasterxml.jackson.databind.JsonNode;
import com.fasterxml.jackson.databind.ObjectMapper;

import java.util.*;

public class JsonFieldSorter {
    public static void main(String[] args) {
        String jsonString = "{\"name\": \"John\", \"age\": 30, \"city\": \"New York\"}";

        try {
            // Step 1: 解析json字符串为Json对象
            ObjectMapper objectMapper = new ObjectMapper();
            JsonNode jsonNode = objectMapper.readTree(jsonString);

            // Step 2: 将Json对象转换为Map对象
            Map<String, JsonNode> map = objectMapper.convertValue(jsonNode, Map.class);

            // Step 3: 对Map对象的键值对进行排序
            Map<String, JsonNode> sortedMap = new TreeMap<>(map);

            // Step 4: 将排序后的Map对象转换回Json对象
            JsonNode sortedJsonNode = objectMapper.convertValue(sortedMap, JsonNode.class);

            // Step 5: 将排序后的Json对象转换为字符串
            String sortedJsonString = objectMapper.writeValueAsString(sortedJsonNode);

            System.out.println(sortedJsonString);
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}