如何在Java中进行列表理解

import java.util.Arrays;
import java.util.List;
import java.util.stream.Collectors;

public class ListComprehensionExample {
    public static void main(String[] args) {
        List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10);

        List<Integer> evenSquares = numbers.stream()
                                           .filter(n -> n % 2 == 0)
                                           .map(n -> n * n)
                                           .collect(Collectors.toList());

        System.out.println(evenSquares); // 输出: [4, 16, 36, 64, 100]
    }
}

import java.util.stream.IntStream;

public class IntStreamExample {
    public static void main(String[] args) {
        int[] numbers = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};

        int sumOfSquares = IntStream.of(numbers)
                                     .filter(n -> n % 2 == 0)
                                     .map(n -> n * n)
                                     .sum();

        System.out.println(sumOfSquares); // 输出: 220
    }
}

import java.util.Arrays;
import java.util.List;
import java.util.stream.Collectors;

class Student {
    private String name;
    private int score;

    public Student(String name, int score) {
        this.name = name;
        this.score = score;
    }

    public String getName() {
        return name;
    }

    public int getScore() {
        return score;
    }
}

public class ComplexStreamExample {
    public static void main(String[] args) {
        List<Student> students = Arrays.asList(
            new Student("Alice", 85),
            new Student("Bob", 75),
            new Student("Charlie", 90),
            new Student("David", 60)
        );

        List<String> highScoreStudents = students.stream()
                                               .filter(s -> s.getScore() > 80)
                                               .map(Student::getName)
                                               .collect(Collectors.toList());

        System.out.println(highScoreStudents); // 输出: [Alice, Charlie]
    }
}