如何在Laravel中获取最新的youtube视频

use GuzzleHttp\Client;

class YoutubeController extends Controller
{
    public function getLatestVideo()
    {
        $apiKey = 'YOUR_YOUTUBE_API_KEY';
        $channelId = 'YOUR_YOUTUBE_CHANNEL_ID';
        $maxResults = 1;

        $client = new Client();
        $response = $client->get("https://www.googleapis.com/youtube/v3/search?key={$apiKey}&channelId={$channelId}&part=snippet,id&order=date&maxResults={$maxResults}");

        $videos = json_decode($response->getBody())->items;

        if (!empty($videos)) {
            $latestVideo = $videos[0];
            $videoId = $latestVideo->id->videoId;
            $videoTitle = $latestVideo->snippet->title;
            $videoDescription = $latestVideo->snippet->description;
            $videoThumbnail = $latestVideo->snippet->thumbnails->default->url;

            // 可以根据需要进行处理和展示
            return view('youtube.latest', compact('videoId', 'videoTitle', 'videoDescription', 'videoThumbnail'));
        } else {
            return view('youtube.latest'); // 没有找到最新视频
        }
    }
}

@if(isset($videoId))
    <div>
        <iframe width="560" height="315" src="https://www.youtube.com/embed/{{ $videoId }}" frameborder="0" allowfullscreen></iframe>
    </div>
    <h2>{{ $videoTitle }}</h2>
    <p>{{ $videoDescription }}</p>
    <img src="{{ $videoThumbnail }}" alt="Video Thumbnail">
@else
    <p>No latest video found.</p>
@endif