在PHP和MySQL中生成循环赛,可以通过以下步骤实现:
CREATE TABLE participants (
id INT AUTO_INCREMENT PRIMARY KEY,
name VARCHAR(255) NOT NULL,
group_id INT NOT NULL
);
CREATE TABLE rounds (
id INT AUTO_INCREMENT PRIMARY KEY,
round_number INT NOT NULL,
participant1_id INT NOT NULL,
participant2_id INT NOT NULL,
winner_id INT,
FOREIGN KEY (participant1_id) REFERENCES participants(id),
FOREIGN KEY (participant2_id) REFERENCES participants(id),
FOREIGN KEY (winner_id) REFERENCES participants(id)
);
<?php
// 获取所有参赛者
$participants = $db->query("SELECT * FROM participants ORDER BY group_id")->fetchAll(PDO::FETCH_ASSOC);
// 获取参赛者数量
$num_participants = count($participants);
// 生成循环赛匹配
for ($i = 0; $i < $num_participants; $i++) {
$round_number = ($i + 1) / 2;
$participant1_id = $participants[$i]['id'];
$participant2_id = $participants[($i + $num_participants / 2) % $num_participants]['id'];
// 插入循环赛匹配信息
$db->query("INSERT INTO rounds (round_number, participant1_id, participant2_id) VALUES ($round_number, $participant1_id, $participant2_id)");
}
<?php
// 查询循环赛匹配信息
$rounds = $db->query("SELECT * FROM rounds ORDER BY round_number")->fetchAll(PDO::FETCH_ASSOC);
// 输出循环赛匹配信息
foreach ($rounds as $round) {
$participant1 = $db->query("SELECT name FROM participants WHERE id = {$round['participant1_id']}")->fetchColumn();
$participant2 = $db->query("SELECT name FROM participants WHERE id = {$round['participant2_id']}")->fetchColumn();
$winner = $round['winner_id'] ? $db->query("SELECT name FROM participants WHERE id = {$round['winner_id']}")->fetchColumn() : '';
echo "Round {$round['round_number']}: {$participant1} vs {$participant2} - Winner: {$winner}\n";
}
通过以上步骤,可以在PHP和MySQL中生成循环赛。
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