如何在PowerMock中使用EasyMock模拟消费者参数

<dependency>
    <groupId>org.powermock</groupId>
    <artifactId>powermock-core</artifactId>
    <version>2.0.9</version>
    <scope>test</scope>
</dependency>

<dependency>
    <groupId>org.powermock</groupId>
    <artifactId>powermock-module-junit4</artifactId>
    <version>2.0.9</version>
    <scope>test</scope>
</dependency>

<dependency>
    <groupId>org.easymock</groupId>
    <artifactId>easymock</artifactId>
    <version>4.3.2</version>
    <scope>test</scope>
</dependency>

public class MyClass {
    public void processData(Consumer<String> consumer) {
        // 处理数据的逻辑
        consumer.accept("data");
    }
}

public class MyConsumer implements Consumer<String> {
    @Override
    public void accept(String data) {
        // 模拟消费者逻辑
    }
}

import org.easymock.EasyMock;
import org.junit.Test;
import org.junit.runner.RunWith;
import org.powermock.api.easymock.PowerMock;
import org.powermock.core.classloader.annotations.PrepareForTest;
import org.powermock.modules.junit4.PowerMockRunner;

@RunWith(PowerMockRunner.class)
@PrepareForTest(MyClass.class)
public class MyClassTest {
    @Test
    public void testProcessData() {
        // 创建一个模拟的消费者对象
        MyConsumer mockConsumer = EasyMock.createMock(MyConsumer.class);

        // 设置模拟的消费者行为
        mockConsumer.accept("data");
        EasyMock.expectLastCall();

        // 使用PowerMock模拟静态方法
        PowerMock.mockStatic(MyClass.class);
        EasyMock.expect(MyClass.class, "processData", EasyMock.anyObject(MyConsumer.class)).andReturn(null);

        // 进行测试
        PowerMock.replayAll();
        MyClass myClass = new MyClass();
        myClass.processData(mockConsumer);
        PowerMock.verifyAll();
    }
}