如何在Python中将url字符串拆分为单独的部分？

from urllib.parse import urlparse, parse_qs

url = "https://www.example.com/path/to/page?param1=value1&param2=value2"

# 使用urlparse函数将URL字符串拆分为单独的部分
parsed_url = urlparse(url)

# 提取URL的各个部分
scheme = parsed_url.scheme
netloc = parsed_url.netloc
path = parsed_url.path
query = parsed_url.query

# 使用parse_qs函数将查询字符串拆分为单独的参数
params = parse_qs(query)

# 输出结果
print("URL scheme:", scheme)
print("URL network location:", netloc)
print("URL path:", path)
print("URL query:", query)
print("URL parameters:", params)

URL scheme: https
URL network location: www.example.com
URL path: /path/to/page
URL query: param1=value1&param2=value2
URL parameters: {'param1': ['value1'], 'param2': ['value2']}