如何在Scala中解析来自JSON的泛型类参数？

libraryDependencies += "io.circe" %% "circe-core" % "0.14.1"
libraryDependencies += "io.circe" %% "circe-generic" % "0.14.1"
libraryDependencies += "io.circe" %% "circe-parser" % "0.14.1"

import io.circe._
import io.circe.parser._
import io.circe.generic.semiauto._

case class Response[T](status: String, data: T)

object Response {
  implicit def decoder[T: Decoder]: Decoder[Response[T]] = deriveDecoder[Response[T]]
}

val jsonStr = """{"status":"success","data":{"name":"John","age":30}}"""
val json = parse(jsonStr).getOrElse(Json.Null)

val response = json.as[Response[Person]]
response match {
  case Right(result) => println(result)
  case Left(error) => println(s"Failed to parse JSON: $error")
}