如何在antlr4访问器方法中抛出异常？

import org.antlr.v4.runtime.*;
import org.antlr.v4.runtime.tree.*;

public class MyVisitor extends YourGrammarBaseVisitor<String> {
    @Override
    public String visitYourRule(YourGrammarParser.YourRuleContext ctx) {
        if (someCondition) {
            String errorMsg = "Some error message";
            RecognitionException ex = new RecognitionException(null, null, null, null);
            ctx.addErrorListener(new BaseErrorListener() {
                @Override
                public void syntaxError(Recognizer<?, ?> recognizer, Object offendingSymbol,
                                        int line, int charPositionInLine, String msg, RecognitionException e) {
                    throw new RuntimeException(errorMsg); // 抛出异常
                }
            });
            throw new RuntimeException(errorMsg); // 抛出异常
        }
        return visitChildren(ctx);
    }
}