如何在java servlet上过滤JSON结果中的记录

import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.databind.node.ArrayNode;
import com.fasterxml.jackson.databind.node.ObjectNode;

// 假设你已经获取到了JSON结果的字符串
String jsonResult = "[{\"name\":\"John\",\"age\":30},{\"name\":\"Jane\",\"age\":25},{\"name\":\"Bob\",\"age\":35}]";

// 使用Jackson库解析JSON字符串为Java对象
ObjectMapper objectMapper = new ObjectMapper();
ArrayNode jsonArray = objectMapper.readValue(jsonResult, ArrayNode.class);

// 过滤记录
ArrayNode filteredArray = objectMapper.createArrayNode();
for (int i = 0; i < jsonArray.size(); i++) {
    ObjectNode record = (ObjectNode) jsonArray.get(i);
    int age = record.get("age").asInt();
    if (age > 30) {
        filteredArray.add(record);
    }
}

// 将过滤后的结果转换为JSON字符串
String filteredJsonResult = objectMapper.writeValueAsString(filteredArray);

// 返回过滤后的JSON结果
response.setContentType("application/json");
response.getWriter().write(filteredJsonResult);