如何在java中使用递归逻辑来查找直接或间接向特定经理报告的经理列表

import java.util.ArrayList;
import java.util.List;

public class Employee {
    private int id;
    private String name;
    private int managerId;

    // 构造函数和getter/setter方法省略

    public static List<Integer> findReportingManagers(int managerId, List<Employee> employees) {
        List<Integer> result = new ArrayList<>();

        for (Employee employee : employees) {
            if (employee.getManagerId() == managerId) {
                result.add(employee.getId());
                result.addAll(findReportingManagers(employee.getId(), employees));
            }
        }

        return result;
    }

    public static void main(String[] args) {
        // 创建员工列表
        List<Employee> employees = new ArrayList<>();
        employees.add(new Employee(1, "Alice", 3));
        employees.add(new Employee(2, "Bob", 3));
        employees.add(new Employee(3, "Charlie", 4));
        employees.add(new Employee(4, "David", 5));
        employees.add(new Employee(5, "Eve", 6));
        employees.add(new Employee(6, "Frank", 7));

        // 查找直接或间接向经理ID为4的经理报告的经理列表
        List<Integer> reportingManagers = Employee.findReportingManagers(4, employees);

        // 输出结果
        System.out.println("Reporting Managers: " + reportingManagers);
    }
}