如何在javascript中比较两个数组的多项选择

function compareArrays(arr1, arr2) {
  if(arr1.length !== arr2.length) {
    return false;
  }
  for(let i = 0; i < arr1.length; i++) {
    if(!arr2.includes(arr1[i])) {
      return false;
    }
  }
  return true;
}

const array1 = [1, 2, 3, 4, 5];
const array2 = [3, 2, 1, 4, 5];
console.log(compareArrays(array1, array2));  // 输出：true

function compareArrays(arr1, arr2) {
  if(arr1.length !== arr2.length) {
    return false;
  }
  const set1 = new Set(arr1);
  const set2 = new Set(arr2);
  for(let item of set1) {
    if(!set2.has(item)) {
      return false;
    }
  }
  return true;
}

const array1 = [1, 2, 3, 4, 5];
const array2 = [3, 2, 1, 4, 5];
console.log(compareArrays(array1, array2));  // 输出：true

function compareArrays(arr1, arr2) {
  if(arr1.length !== arr2.length) {
    return false;
  }
  return arr1.every(item => arr2.includes(item));
}

const array1 = [1, 2, 3, 4, 5];
const array2 = [3, 2, 1, 4, 5];
console.log(compareArrays(array1, array2));  // 输出：true