如何在php中显示从数据库中选择的值并在多个选择框中显示

<?php
// 数据库连接配置
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "database_name";

// 创建连接
$conn = new mysqli($servername, $username, $password, $dbname);

// 检查连接
if ($conn->connect_error) {
    die("连接失败: " . $conn->connect_error);
}

// 查询语句
$sql = "SELECT id, name FROM your_table";
$result = $conn->query($sql);

// 检查是否有结果
if ($result->num_rows > 0) {
    echo "<select name='your_select_box' multiple>";
    while($row = $result->fetch_assoc()) {
        echo "<option value='" . $row["id"] . "'>" . $row["name"] . "</option>";
    }
    echo "</select>";
} else {
    echo "0 结果";
}

// 关闭连接
$conn->close();
?>