如何在python中将平衡二叉树的结果保存为数组

class TreeNode:
    def __init__(self, val=0, left=None, right=None):
        self.val = val
        self.left = left
        self.right = right

def inorderTraversal(root):
    if not root:
        return []
    result = []
    result += inorderTraversal(root.left)
    result.append(root.val)
    result += inorderTraversal(root.right)
    return result

# 示例用法
# 构造一个平衡二叉树
root = TreeNode(1)
root.left = TreeNode(2)
root.right = TreeNode(3)
root.left.left = TreeNode(4)
root.left.right = TreeNode(5)
root.right.left = TreeNode(6)
root.right.right = TreeNode(7)

# 将平衡二叉树的结果保存为数组
result_array = inorderTraversal(root)
print(result_array)