如何在react native中显示作为对象传递到另一个屏幕的状态

npm install @react-navigation/native

import React from 'react';
import { NavigationContainer } from '@react-navigation/native';
import { createStackNavigator } from '@react-navigation/stack';
import ScreenA from './ScreenA';
import ScreenB from './ScreenB';

const Stack = createStackNavigator();

const App = () => {
  return (
    <NavigationContainer>
      <Stack.Navigator>
        <Stack.Screen name="ScreenA" component={ScreenA} />
        <Stack.Screen name="ScreenB" component={ScreenB} />
      </Stack.Navigator>
    </NavigationContainer>
  );
};

export default App;

import React, { useState } from 'react';
import { View, Button } from 'react-native';

const ScreenA = ({ navigation }) => {
  const [status, setStatus] = useState('Hello from Screen A');

  const goToScreenB = () => {
    navigation.navigate('ScreenB', { status });
  };

  return (
    <View>
      <Button title="Go to Screen B" onPress={goToScreenB} />
    </View>
  );
};

export default ScreenA;

import React from 'react';
import { View, Text } from 'react-native';

const ScreenB = ({ route }) => {
  const { status } = route.params;

  return (
    <View>
      <Text>{status}</Text>
    </View>
  );
};

export default ScreenB;