如何在react native中显示向外滑动显示右侧默认按钮

import Swipeable from 'react-native-gesture-handler/Swipeable';

<Swipeable
  renderRightActions={renderRightActions}
  onSwipeableRightOpen={onSwipeableRightOpen}
>
  {/* 在这里放置你的内容 */}
</Swipeable>

const renderRightActions = () => (
  <View style={styles.rightActions}>
    <TouchableOpacity onPress={handleButtonPress}>
      <Text style={styles.buttonText}>按钮</Text>
    </TouchableOpacity>
  </View>
);

const onSwipeableRightOpen = () => {
  // 在这里执行相应的操作
};

const styles = StyleSheet.create({
  rightActions: {
    flex: 1,
    justifyContent: 'center',
    alignItems: 'flex-end',
    backgroundColor: 'red',
  },
  buttonText: {
    color: 'white',
    paddingHorizontal: 10,
    paddingVertical: 5,
  },
});