如何在scala中将函数的输出结果作为PUT请求提供？

libraryDependencies += "com.typesafe.akka" %% "akka-http" % "2.6.15"

import akka.actor.ActorSystem
import akka.http.scaladsl.Http
import akka.http.scaladsl.model._
import akka.stream.ActorMaterializer

import scala.concurrent.Future

object Main extends App {
  // 创建Actor System
  implicit val system = ActorSystem()
  implicit val materializer = ActorMaterializer()
  implicit val executionContext = system.dispatcher

  // 函数示例，将输入参数x加倍
  def doubleValue(x: Int): Int = x * 2

  // 创建PUT请求的URL和内容
  val url = "https://example.com/api/resource"  // 替换为实际的URL
  val inputValue = 5  // 替换为实际的输入值
  val putRequest = HttpRequest(
    method = HttpMethods.PUT,
    uri = url,
    entity = HttpEntity(ContentTypes.`application/json`, doubleValue(inputValue).toString)
  )

  // 发送PUT请求，并获取响应
  val responseFuture: Future[HttpResponse] = Http().singleRequest(putRequest)

  responseFuture.onComplete { response =>
    response match {
      case scala.util.Success(res) =>
        // 处理成功响应
        println(s"Request successful. Response code: ${res.status}")
        res.entity.toStrict(5.seconds).map(_.data.utf8String).map { responseBody =>
          println(s"Response body: $responseBody")
          // 在这里可以对响应进行进一步处理
        }
      case scala.util.Failure(ex) =>
        // 处理请求失败
        println(s"Request failed: ${ex.getMessage}")
    }
    // 关闭Actor System
    system.terminate()
  }
}