如何将两个u8和u16元素数组合并为一个u8元素数组？

#include <stdio.h>
#include <stdint.h>

uint8_t* mergeArrays(uint8_t* u8_array, uint16_t* u16_array, int u8_length, int u16_length) {
    int merged_length = u8_length + u16_length;
    uint8_t* merged_array = (uint8_t*)malloc(merged_length * sizeof(uint8_t));

    // 复制第一个u8数组
    for (int i = 0; i < u8_length; i++) {
        merged_array[i] = u8_array[i];
    }

    // 转换并复制第二个u16数组
    for (int i = 0; i < u16_length; i++) {
        merged_array[u8_length + i] = (uint8_t)(u16_array[i] & 0xFF);
    }

    return merged_array;
}

int main() {
    uint8_t u8_array[] = { 1, 2, 3 };
    uint16_t u16_array[] = { 256, 512, 1024 };

    int u8_length = sizeof(u8_array) / sizeof(uint8_t);
    int u16_length = sizeof(u16_array) / sizeof(uint16_t);

    uint8_t* merged_array = mergeArrays(u8_array, u16_array, u8_length, u16_length);

    printf("Merged Array: ");
    for (int i = 0; i < u8_length + u16_length; i++) {
        printf("%d ", merged_array[i]);
    }
    printf("\n");

    free(merged_array);

    return 0;
}