如何将从.csv文件中获取的getline字符串转换为int类型才能使用它

#include <iostream>
#include <fstream>
#include <sstream>
#include <string>

int main() {
    std::ifstream file("data.csv"); // 假设CSV文件名为data.csv
    std::string line;

    if (!file.is_open()) {
        std::cerr << "Failed to open file." << std::endl;
        return 1;
    }

    while (getline(file, line)) {
        std::istringstream ss(line);
        std::string cell;
        int number;

        while (getline(ss, cell, ',')) { // 假设CSV使用逗号分隔
            try {
                number = std::stoi(cell); // 将字符串转换为整数
                std::cout << "Converted number: " << number << std::endl;
            } catch (const std::invalid_argument& e) {
                std::cerr << "Invalid argument: " << cell << " is not a valid number." << std::endl;
            } catch (const std::out_of_range& e) {
                std::cerr << "Out of range: " << cell << " is too large or too small for an int." << std::endl;
            }
        }
    }

    file.close();
    return 0;
}