如何将十六进制字符串转换为uint8_t *数组？

#include <iostream>
#include <string>
#include <sstream>

// 将十六进制字符转换为对应的十进制数值
uint8_t hexCharToDecimal(char c) {
    if (c >= '0' && c <= '9') {
        return c - '0';
    } else if (c >= 'a' && c <= 'f') {
        return c - 'a' + 10;
    } else if (c >= 'A' && c <= 'F') {
        return c - 'A' + 10;
    }
    return 0;
}

// 将十六进制字符串转换为uint8_t *数组
uint8_t* hexStringToUint8Array(const std::string& hexString, size_t& arraySize) {
    // 计算数组大小
    arraySize = hexString.length() / 2;

    // 创建uint8_t *数组
    uint8_t* uint8Array = new uint8_t[arraySize];

    // 遍历字符数组，转换为uint8_t类型
    for (size_t i = 0; i < arraySize; i++) {
        uint8Array[i] = (hexCharToDecimal(hexString[i * 2]) << 4) + hexCharToDecimal(hexString[i * 2 + 1]);
    }

    return uint8Array;
}

int main() {
    std::string hexString = "48656C6C6F20576F726C64";
    size_t arraySize = 0;
    uint8_t* uint8Array = hexStringToUint8Array(hexString, arraySize);

    // 打印转换后的uint8_t *数组
    for (size_t i = 0; i < arraySize; i++) {
        std::cout << std::hex << static_cast<int>(uint8Array[i]) << " ";
    }
    std::cout << std::endl;

    // 释放内存
    delete[] uint8Array;

    return 0;
}