如何将通用属性作为参数传递给函数？

def func(*args, **kwargs):
    for arg in args:
        print(arg)


func(1, 2, 3, 4, 5)  # 输出: (1, 2, 3, 4, 5)
func(name="John", age=30, city="New York")  # 输出: ('John', 30, 'New York')

def func_custom_params(*args, custom_arg="default_value", **kwargs):
    for arg in args:
        print(arg)

func_custom_params(custom_arg="custom")  # 输出: custom_arg='custom'
func_custom_params(1, 2, 3, 4, 5)  # 输出: (1, 2, 3, 4, 5)

def custom_param(custom_parameter):
    return custom_parameter

custom_param1 = custom_param(1, 2, 3)
custom_param2 = custom_param(custom_number=4)  # custom_number是一个独立的名称参数

def func_tuple(arg1, *args):
    for arg in args:
        print(f"arg: {arg}")

func_tuple(1, 2, 3)  # 输出: arg: 1 arg: 2 arg: 3