如何将id传递给函数以从列表中删除项

def delete_item_by_id(lst, item_id):
    for item in lst:
        if item['id'] == item_id:
            lst.remove(item)
            break

# 示例用法
my_list = [{'id': 1, 'name': 'item1'}, {'id': 2, 'name': 'item2'}, {'id': 3, 'name': 'item3'}]
delete_item_by_id(my_list, 2)
print(my_list)  # 输出: [{'id': 1, 'name': 'item1'}, {'id': 3, 'name': 'item3'}]

class Item:
    def __init__(self, item_id, name):
        self.id = item_id
        self.name = name

def delete_item_by_id(lst, item_id):
    for item in lst:
        if item.id == item_id:
            lst.remove(item)
            break

# 示例用法
my_list = [Item(1, 'item1'), Item(2, 'item2'), Item(3, 'item3')]
delete_item_by_id(my_list, 2)
print(my_list)  # 输出: [<__main__.Item object at 0x...>, <__main__.Item object at 0x...>]