如何将json date time序列化为joda-time

import com.fasterxml.jackson.databind.ObjectMapper;

// JSON字符串
String json = "{\"date\":\"2022-01-01\", \"time\":\"10:30:00\"}";

// 创建ObjectMapper对象
ObjectMapper objectMapper = new ObjectMapper();

// 将JSON字符串解析为JSON对象
JsonNode jsonNode = objectMapper.readTree(json);

import org.joda.time.DateTime;
import org.joda.time.format.DateTimeFormat;
import org.joda.time.format.DateTimeFormatter;

// 获取日期时间字符串
String dateString = jsonNode.get("date").asText();
String timeString = jsonNode.get("time").asText();

// 定义日期时间格式
String pattern = "yyyy-MM-dd HH:mm:ss";
DateTimeFormatter formatter = DateTimeFormat.forPattern(pattern);

// 将日期时间字符串转换为Joda-Time对象
DateTime dateTime = formatter.parseDateTime(dateString + " " + timeString);