如何将lambda返回给thenComparing方法

import java.util.ArrayList;
import java.util.Comparator;
import java.util.List;

public class LambdaSortingExample {
    public static void main(String[] args) {
        List<Person> persons = new ArrayList<>();
        persons.add(new Person("John", 25));
        persons.add(new Person("Alice", 30));
        persons.add(new Person("Bob", 20));

        // 使用lambda表达式返回给thenComparing方法
        Comparator<Person> comparator = Comparator.comparing(Person::getName)
                .thenComparing(Person::getAge);

        // 对集合进行排序
        persons.sort(comparator);

        // 输出排序结果
        for (Person person : persons) {
            System.out.println(person.getName() + " - " + person.getAge());
        }
    }
}

class Person {
    private String name;
    private int age;

    public Person(String name, int age) {
        this.name = name;
        this.age = age;
    }

    public String getName() {
        return name;
    }

    public int getAge() {
        return age;
    }
}