如何将uint32_t号转换为char[8]？

#include <iostream>
#include <cstring>

void convertUint32ToChar(uint32_t num, char* arr) {
    arr[0] = (num >> 24) & 0xFF;
    arr[1] = (num >> 16) & 0xFF;
    arr[2] = (num >> 8) & 0xFF;
    arr[3] = num & 0xFF;
    arr[4] = '\0'; // Add null character to terminate the string
}

int main() {
    uint32_t number = 12345678;
    char charArray[8];

    convertUint32ToChar(number, charArray);

    std::cout << "Converted char array: " << charArray << std::endl;

    return 0;
}