如何找出一个文件中有多少阶乘数

import re

def count_factorials_in_file(file_path):
    count = 0

    with open(file_path, 'r') as file:
        for line in file:
            numbers = re.findall(r'\d+', line)  # 提取数字
            for number in numbers:
                num = int(number)
                factorial = 1
                i = 1
                while factorial <= num:
                    if factorial == num:
                        count += 1
                        break
                    i += 1
                    factorial *= i

    return count

file_path = 'example.txt'  # 替换为实际文件路径
result = count_factorials_in_file(file_path)
print("文件中的阶乘数数量为:", result)