如何找到给定月份的第n个DayOfWeek？

import datetime

def find_nth_day_of_week(year, month, n, day_of_week):
    # 将星期几转换为对应的weekday()返回值，其中星期一为0，星期日为6
    day_of_week_index = day_of_week - 1
    
    # 初始化日期为该月的第一天
    date = datetime.date(year, month, 1)
    
    # 计算到下一个指定星期几的天数
    days_to_next = (day_of_week_index - date.weekday()) % 7
    if days_to_next == 0 and n > 1:
        days_to_next += 7  # 如果第一天就是指定的星期几，且n>1，则跳过这一天
    
    # 跳过前面的天数，找到第n个指定星期几
    for _ in range(n - 1):
        date += datetime.timedelta(days=7)
        days_to_next = (day_of_week_index - date.weekday()) % 7
        if days_to_next == 0:
            date += datetime.timedelta(days=7)  # 跳过整周的情况
    
    return date

# 示例：找到2023年4月的第3个星期二
year = 2023
month = 4
n = 3
day_of_week = 2  # 星期二
result_date = find_nth_day_of_week(year, month, n, day_of_week)
print(result_date)  # 输出结果日期