如何支持GraphqlJava查询中的排序

// 定义GraphQL Schema
GraphQLObjectType queryType = newObject()
    .name("Query")
    .field(newFieldDefinition()
        .name("users")
        .type(newList(userType))
        .argument(GraphQLArgument.newArgument()
            .name("sortField")
            .type(Scalars.GraphQLString))
        .argument(GraphQLArgument.newArgument()
            .name("sortOrder")
            .type(Scalars.GraphQLString))
        .dataFetcher(environment -> {
            // 获取传入的参数
            String sortField = environment.getArgument("sortField");
            String sortOrder = environment.getArgument("sortOrder");

            // 根据参数进行排序操作
            List<User> sortedUsers = getUsersFromDatabase();
            if (sortField != null && sortOrder != null) {
                // 使用Java的排序算法对结果进行排序
                Collections.sort(sortedUsers, new UserComparator(sortField, sortOrder));
            }

            return sortedUsers;
        }))
    .build();

// 定义User类型
GraphQLObjectType userType = newObject()
    .name("User")
    .field(newFieldDefinition()
        .name("id")
        .type(Scalars.GraphQLInt))
    .field(newFieldDefinition()
        .name("name")
        .type(Scalars.GraphQLString))
    .build();

// 定义GraphQL Schema
GraphQLSchema schema = GraphQLSchema.newSchema()
    .query(queryType)
    .build();

// 创建GraphQL执行器
GraphQL graphQL = GraphQL.newGraphQL(schema).build();

// 执行查询
ExecutionResult result = graphQL.execute("{ users(sortField: \"name\", sortOrder: \"ASC\") { id name } }");
Map<String, Object> resultMap = result.getData();