如何构造具有Excel表格文件的InputStream的响应体？

import org.apache.poi.ss.usermodel.*;

import java.io.ByteArrayInputStream;
import java.io.ByteArrayOutputStream;
import java.io.IOException;
import javax.servlet.http.HttpServletResponse;

public class ExcelResponseBuilder {
    public static void buildExcelResponse(HttpServletResponse response) throws IOException {
        // 创建空的工作簿
        Workbook workbook = WorkbookFactory.create(true);

        // 创建工作表
        Sheet sheet = workbook.createSheet("Sheet1");

        // 创建行和单元格，并设置值
        Row row = sheet.createRow(0);
        Cell cell = row.createCell(0);
        cell.setCellValue("Hello");

        // 将工作簿写入输出流中
        ByteArrayOutputStream outputStream = new ByteArrayOutputStream();
        workbook.write(outputStream);

        // 将输出流转换为输入流
        ByteArrayInputStream inputStream = new ByteArrayInputStream(outputStream.toByteArray());

        // 设置响应头，指定内容类型为Excel文件
        response.setContentType("application/vnd.ms-excel");

        // 设置响应头，指定文件名为example.xlsx
        response.setHeader("Content-Disposition", "attachment; filename=example.xlsx");

        // 将输入流写入响应体
        byte[] buffer = new byte[1024];
        int bytesRead;
        while ((bytesRead = inputStream.read(buffer)) != -1) {
            response.getOutputStream().write(buffer, 0, bytesRead);
        }

        // 关闭输入流和输出流
        inputStream.close();
        outputStream.close();
    }
}