我正试图反向设计一个函数来获取输入。假设我们知道输出(x)。有可能得到输入(z)吗?函数的代码如下所示 var uint_1 = 1372797859u; ulong a = (ulong)z; for (int i = 0; i < 32; i += 1) if ((uint_2 & 1u) != 0u) x = (uint)((ulong)x
开关上添加了帮助中的信息: also require SMTdisabled + unconditional L1D flush to deem Foreshadow-NG VMM as mitigated* Information from the /sys interface: Mitigation: PTE Inv