如何根据两个txt文件中的相对词频对词典进行排序

import re

# 读取txt文件并统计词频
def count_word_frequency(file_path):
    word_frequency = {}
    with open(file_path, 'r') as file:
        for line in file:
            words = re.findall(r'\w+', line.lower())
            for word in words:
                if word in word_frequency:
                    word_frequency[word] += 1
                else:
                    word_frequency[word] = 1
    return word_frequency

# 合并两个词频字典
def merge_word_frequency(dict1, dict2):
    merged_dict = dict1.copy()
    for word, frequency in dict2.items():
        if word in merged_dict:
            merged_dict[word] += frequency
        else:
            merged_dict[word] = frequency
    return merged_dict

# 根据词频对词典进行排序
def sort_word_frequency(word_frequency):
    sorted_frequency = sorted(word_frequency.items(), key=lambda x: x[1], reverse=True)
    return sorted_frequency

# 输出排序结果到txt文件
def output_sorted_result(sorted_frequency, output_file):
    with open(output_file, 'w') as file:
        for word, frequency in sorted_frequency:
            file.write(f"{word}: {frequency}\n")

# 主函数
def main():
    file1 = 'file1.txt'
    file2 = 'file2.txt'
    output_file = 'sorted_dict.txt'

    dict1 = count_word_frequency(file1)
    dict2 = count_word_frequency(file2)
    merged_dict = merge_word_frequency(dict1, dict2)
    sorted_frequency = sort_word_frequency(merged_dict)
    output_sorted_result(sorted_frequency, output_file)

if __name__ == '__main__':
    main()