如何根据每个值最早的2个日期返回值

def get_earliest_values(data):
    # 按日期排序
    sorted_data = sorted(data, key=lambda x: x['date'])
    
    # 记录每个值的最早两个日期
    earliest_dates = {}
    
    for item in sorted_data:
        value = item['value']
        date = item['date']
        
        if value not in earliest_dates:
            earliest_dates[value] = [date]
        else:
            earliest_dates[value].append(date)
        
        # 只保留最早的两个日期
        earliest_dates[value] = sorted(earliest_dates[value])[:2]
    
    # 根据记录的最早两个日期返回值
    earliest_values = []
    
    for value, dates in earliest_dates.items():
        for date in dates:
            earliest_values.append({
                'value': value,
                'date': date
            })
    
    return earliest_values