如何正确堆叠numpy数组？

import numpy as np

a = np.array([[1, 2], [3, 4]])
b = np.array([[5, 6]])

result = np.vstack((a, b))
print(result)
# 输出:
# [[1 2]
#  [3 4]
#  [5 6]]

import numpy as np

a = np.array([[1, 2], [3, 4]])
b = np.array([[5], [6]])

result = np.hstack((a, b))
print(result)
# 输出:
# [[1 2 5]
#  [3 4 6]]

import numpy as np

a = np.array([[1, 2], [3, 4]])
b = np.array([[5, 6], [7, 8]])

result = np.dstack((a, b))
print(result)
# 输出:
# [[[1 5]
#   [2 6]]
#
#  [[3 7]
#   [4 8]]]

import numpy as np

a = np.array([[1, 2], [3, 4]])
b = np.array([[5, 6]])

# 沿第一个轴（行）堆叠
result_axis_0 = np.concatenate((a, b), axis=0)
print(result_axis_0)
# 输出:
# [[1 2]
#  [3 4]
#  [5 6]]

# 沿第二个轴（列）堆叠
result_axis_1 = np.concatenate((a, b.T), axis=1)
print(result_axis_1)
# 输出:
# [[1 2 5]
#  [3 4 6]]

import numpy as np

a = np.array([[1, 2], [3, 4]])
b = np.array([5, 6])  # 形状为 (2,)，需要调整为 (1, 2)

b = b.reshape(1, -1)  # 调整形状为 (1, 2)
result = np.vstack((a, b))
print(result)
# 输出:
# [[1 2]
#  [3 4]
#  [5 6]]