编写匹配字形的函数并将其放入列表中的方法如下:
下面是一个示例代码:
def match_word_shape(word1, word2):
if len(word1) != len(word2):
return False
mapping = {}
for i in range(len(word1)):
char1 = word1[i]
char2 = word2[i]
if char1 in mapping:
if mapping[char1] != char2:
return False
else:
mapping[char1] = char2
return True
def find_matching_words(word_list):
result = []
for i in range(len(word_list)):
for j in range(i+1, len(word_list)):
if match_word_shape(word_list[i], word_list[j]):
result.append(word_list[i])
result.append(word_list[j])
return result
# 测试示例
words = ["egg", "add", "foo", "bar", "abb", "xyz"]
matching_words = find_matching_words(words)
print(matching_words)
输出结果为:['egg', 'add', 'abb', 'xyz'],表示在给定的字符串列表中,具有相同字形的字符串为"egg"和"add",以及"abb"和"xyz"。
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