如何舍入双精度值以删除连续的9或0

import re

def round_double_value(value):
    # 将双精度值转换为字符串
    value_str = str(value)
    
    # 匹配连续的9或0
    pattern = re.compile(r'9+|0+')
    matches = pattern.findall(value_str)
    
    # 替换匹配到的连续9或0为空字符串
    for match in matches:
        value_str = value_str.replace(match, '')
    
    # 将处理后的字符串转换回双精度值
    rounded_value = float(value_str)
    
    return rounded_value

# 示例使用
value = 123.990000009
rounded_value = round_double_value(value)
print(rounded_value)