如何获取文件描述(产品名称、原始文件名等)在windows中使用golang？

import (
    "os"
    "syscall"
)

file, err := os.Open("文件路径")
if err != nil {
    // 处理打开文件错误
}
defer file.Close()

var fileInfo syscall.ByHandleFileInformation
err = syscall.GetFileInformationByHandle(syscall.Handle(file.Fd()), &fileInfo)
if err != nil {
    // 处理获取文件信息错误
}

productName := syscall.UTF16ToString(fileInfo.FileName[:])
originalFileName := syscall.UTF16ToString(fileInfo.AlternateFileName[:])

package main

import (
    "fmt"
    "os"
    "syscall"
)

func main() {
    file, err := os.Open("文件路径")
    if err != nil {
        fmt.Println("打开文件错误:", err)
        return
    }
    defer file.Close()

    var fileInfo syscall.ByHandleFileInformation
    err = syscall.GetFileInformationByHandle(syscall.Handle(file.Fd()), &fileInfo)
    if err != nil {
        fmt.Println("获取文件信息错误:", err)
        return
    }

    productName := syscall.UTF16ToString(fileInfo.FileName[:])
    originalFileName := syscall.UTF16ToString(fileInfo.AlternateFileName[:])

    fmt.Println("产品名称:", productName)
    fmt.Println("原始文件名:", originalFileName)
}